Be the first to review “Solution Manual for Numerical Analysis, 9th Edition Richard L. Douglas Faires” Cancel reply You must be logged in to post a comment. Student Solutions Manual with Study Guide for Burden/Faires' Numerical Analysis, 9th 9th edition by Burden, Richard L., Faires, J. Douglas (2010) Paperback Paperback – 1600 3.2 out of 5 stars 67 customer reviews.

Chapter 1

Mathematical Preliminaries And Error Analysis

Chapter 2

Solutions Of Equations In One Variable

Chapter 3

Interpolation And Polynomial Approximation

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Chapter 4

Numerical Differentiation And Integration

Numerical Analysis Burden Solutions Manual 9th Edition Download Full

Chapter 5

Initial-Value Problems For Ordinary Differential Equations

Chapter 6

Direct Methods For Solving Linear Systems

Chapter 7

Iterative Techniques In Matrix Algebra

Chapter 8

Approximation Theory

Chapter 9

Approximating Eigenvalues

Chapter 10

Numerical Solutions Of Nonlinear Systems Of Equations

Chapter 11

Boundary-Value Problems For Ordinary Differential Equations

Chapter 12

Numerical Solutions To Partial Differential Equations

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Burden Numerical Analysis Solution Pdf

• Step 1 of 11

  To construct interpolation polynomial of degree two consider allthe three nodal points

  i.e.

  Now take,we get

  , and

  We first determine the coefficient polynomial

  and

  Now the interpolate polynomial of degree two

  taking,

  • where did the x=0.45 come from?
  • oh nevermind
• Step 2 of 11
  = 0.900447

  and by using calculator

  = 0.898100

  Therefore the absolute error,

  • this answer is incorrect. should be 1.204998
  • how come should it be 1.204998?
  • No moron, the answer is correct.
  • nuuuuuuw
  • missing the degree of 1 part.
  • missing the first part where a polynomial of degree one is constructed
• Step 3 of 11

  Free 32 bit games. (b) We are given with

  To construct interpolation polynomial of degree one, consideronly two nodal points

  Now take,we get

  and

  We first determine the coefficient polynomial

  Now the interpolate polynomial of degree one

  taking,

  = 1.204159

  and

  = 1.198683

  Therefore the absolute error,

  • .441518(.45) + 1
  • Therefore, absolute error must equal approximately 1.005476
  • no you are wrong the absolute error is 0.005476.
  • Given answer is correct though they forgot to show the +1 it is still computed. .441518(.45) = 0.1986831 0.1986831+1 = 1.198
• Step 4 of 11

  To construct interpolation polynomial of degree two consider allthe three nodal points

  i.e.

  Now take,we get

  , and

  We first determine the coefficient polynomial

  and

• Step 5 of 11

  Now the interpolate polynomial of degree two

  and by using calculator

  = 1.203423

  taking,

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  = 1.204159

  Therefore the absolute error,

• Step 6 of 11

  (c) We are given with

  To construct interpolation polynomial of degree one, consideronly two nodal points

  Now take,we get

  and

  We first determine the coefficient polynomial

  Now the interpolate polynomial of degree one

  taking,

  = 0.371563

  and

  = 0.352502

  Therefore the absolute error,

  = 0.019062

  • wouldn't x_1 and x_2 give a better approximation
  • nah, the values you choose for representing P1(x) must consist 0.45 in them. as in this example: 0.45 belong to (0,0.6)
• Step 7 of 11

  To construct interpolation polynomial of degree two consider allthe three nodal points

  i.e.

  Now take,we get

  , and

  We first determine the coefficient polynomial

• Step 8 of 11

  and

  Now the interpolate polynomial of degree two

  taking,

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  = 0.371563

  and by using calculator

  = 0.368291

  Therefore the absolute error,

  • small mistake here subtract |.368291-.371563|
• Step 9 of 11

  (d) We are given with

  To construct interpolation polynomial of degree one, consideronly two nodal points

  Now take,we get

  and

  We first determine the coefficient polynomial

  Now the interpolate polynomial of degree one

  taking,

  = 0.483055

  and

  = 0.513103

• Step 10 of 11
• Step 11 of 11

  Invaders from the planet moolah free download. To construct interpolation polynomial of degree two consider allthe three nodal points

  i.e.

  Now take,we get

  , and

  We first determine the coefficient polynomial

  and

  Now the interpolate polynomial of degree two

  taking,

  = 0.483055

  and by using calculator

  = 0.454614

  Therefore the absolute error,